Tikal-25 Manual - Examples
TI-25 Examples
The following example problems from the original owner's manual are used to verify the correct operation of the calculator in the application development unit tests, among others. They also show how to key in problems efficiently using the calculators capabilities. The results will vary slightly from the original occasionally because of higher accuracy.
| 1. 3.7 - (-7.09) + 0.014 = 3.404 |
| 3 . 7 +/- - |
-3.7 |
| 7 . 0 9 +/- + |
3.39 |
| . 0 1 4 = |
3.404 |
| 2. -4 × 7.3 ÷ 2 = -14.6 |
| 4 +/- × |
-4 |
| 7 . 3 ÷ |
-29.2 |
| 2 = |
-14.6 |
| 3. 5 + (8 / (9 - 2)) = 6.1428571 |
| 5 + ( |
5 |
| 8 ÷ ( |
8 |
| 9 - |
9 |
| 2 ) |
7 |
| ) |
1.1428571 |
| = |
6.1428571 |
| 4. 3 × (4-(4√7)) = 0.3146477 |
| CLR |
0 |
| 3 × ( |
3 |
| 4 yx ( |
4 |
| 7 INV yx |
7 |
| 4 ) |
1.6265766 |
| +/- |
-1.6265766 |
| ) |
0.1048826 |
| = |
0.3146477 |
| 5. |
| 31 + 1.8026 = 32.8026 |
| 745.797 + 1.8026 = 747.5996 |
| -8.002 + 1.8026 = -6.1994 |
| CLR |
0 |
| 3 1 + 2nd K |
31 |
| 1 . 8 0 2 6 = |
32.8026 |
| 7 4 5 . 7 9 7 = |
747.5996 |
| 8 . 0 0 2 +/- = |
-6.1994 |
New Features Examples
These examples demonstrate additional features
| 1. Define function f0(x,y,z) = 2 x2 + 3.5 x y z + 3 y2 + 6 z3 |
| I 2nd DEFN |
0 |
| 2 × |
2 |
| 2nd x? x2 + |
0 |
| 3 . 5 × |
3.5 |
| 2nd x? × |
0 |
| 2nd y? × |
0 |
| 2nd z? + |
0 |
| 3 × |
3 |
| 2nd y? x2 + |
0 |
| 6 × |
6 |
| 2nd z? yx 3 = |
0 |
| 2. Use function f0(2, 3.5, 4) = 526.75 |
| 2 x= |
2 |
| 3 . 5 y= |
3.5 |
| 4 z= |
4 |
| 0 fn |
526.75 |
| 3. Use function f0(2, 2.8, 4) = 493.92 |
| 2 . 8 y= |
2.8 |
| 0 fn |
493.92 |